How to Extract Script and CSS Files from Web Pages in Python

Building a tool to extract all Javascript and CSS files from a web page in Python using requests and BeautifulSoup.
  · 4 min read · Updated may 2022 · Web Scraping

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Say you're tasked to analyze some website to check for its performance and you need to extract total files required to download for the web page to properly load, in this tutorial, I will help you accomplish that by building a Python tool to extract all script and CSS file links that are linked to a specific website.

We will be using requests and BeautifulSoup as an HTML parser, if you don't have them installed on your Python, please do:

pip3 install requests bs4

Let's start off by initializing the HTTP session and setting the User agent as a regular browser and not a Python bot:

import requests
from bs4 import BeautifulSoup as bs
from urllib.parse import urljoin

# URL of the web page you want to extract
url = ""

# initialize a session
session = requests.Session()
# set the User-agent as a regular browser
session.headers["User-Agent"] = "Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/44.0.2403.157 Safari/537.36"

Now to download all the HTML content of that web page, all we need to do is call session.get() method, which returns a response object, we are interested just in the HTML code, not the entire response:

# get the HTML content
html = session.get(url).content

# parse HTML using beautiful soup
soup = bs(html, "html.parser")

Now we have our soup, let's extract all script and CSS files, we use soup.find_all() method that returns all the HTML soup objects filtered with the tag and attributes passed:

# get the JavaScript files
script_files = []

for script in soup.find_all("script"):
    if script.attrs.get("src"):
        # if the tag has the attribute 'src'
        script_url = urljoin(url, script.attrs.get("src"))

So, basically we are searching for script tags that have the src attribute, this usually links to Javascript files required for this website.

Similarly, we can use it for extract CSS files:

# get the CSS files
css_files = []

for css in soup.find_all("link"):
    if css.attrs.get("href"):
        # if the link tag has the 'href' attribute
        css_url = urljoin(url, css.attrs.get("href"))

As you may know, CSS files are within href attributes in link tags. We are using urljoin() function to make sure the link is an absolute one (i.e with full path, not a relative path such as /js/script.js).

Finally, let's print the total script and CSS files and write the links into seperate files:

print("Total script files in the page:", len(script_files))
print("Total CSS files in the page:", len(css_files))

# write file links into files
with open("javascript_files.txt", "w") as f:
    for js_file in script_files:
        print(js_file, file=f)

with open("css_files.txt", "w") as f:
    for css_file in css_files:
        print(css_file, file=f)

Once you execute it, 2 files will appear, one for Javascript links and the other for CSS files:



Alright, in the end, I encourage you to further extend this code to build a sophisticated audit tool that is able to identify different files, their sizes and maybe can make suggestions to optimize the website !

As a challenge, try to download all these files and store them in your local disk (this tutorial can help).

I have another tutorial to show you how you can extract all website links, check it out here.

Furthermore, if the website you're analyzing accidentally bans your IP address, you need to use a proxy server in that case.

Related: How to Automate Login using Selenium in Python.

Happy Scraping ♥

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